Conditional ternary operator
Verilog has a ternary conditional operator ( ? : ) much like C:
Verilog |
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| (condition ? if_true : if_false)
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This can be used to choose one of two values based on condition (a mux!) on one line, without using an if-then inside a combinational always block.
Examples:
Verilog |
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| (0 ? 3 : 5) // This is 5 because the condition is false.
(sel ? b : a) // A 2-to-1 multiplexer between a and b selected by sel.
always @(posedge clk) // A T-flip-flop.
q <= toggle ? ~q : q;
always @(*) // State transition logic for a one-input FSM
case (state)
A: next = w ? B : A;
B: next = w ? A : B;
endcase
assign out = ena ? q : 1'bz; // A tri-state buffer
((sel[1:0] == 2'h0) ? a : // A 3-to-1 mux
(sel[1:0] == 2'h1) ? b :
c )
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Practice
Problem statement
Given four unsigned numbers, find the minimum. Unsigned numbers can be compared with standard comparison operators (a < b). Use the conditional operator to make two-way min circuits, then compose a few of them to create a 4-way min circuit. You'll probably want some wire vectors for the intermediate results.
Verilog |
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| module top_module (
input [7:0] a, b, c, d,
output [7:0] min);//
// assign intermediate_result1 = compare? true: false;
endmodule
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Solution
Verilog |
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| module top_module (
input [7:0] a, b, c, d,
output [7:0] min);//
wire [7:0] w1,w2;
assign w1=a>b?b:a;
assign w2=c>d?d:c;
assign min=w1>w2?w2:w1;
endmodule
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